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Let the x-z plane be the boundary between two transparent media. Medium 1 in `zge0` has a refractive index of `sqrt2` and medium 2 with `zlt0` has a refractive index of `sqrt3`. A ray of light in medium 1 given by the vector `vecA=6sqrt3hati+8sqrt3hatj-10hatk` is incident on the plane of separation. The angle of refraction in medium 2 is:

A

`45^circ`

B

`60^circ`

C

`74^circ`

D

`30^circ`

Text Solution

Verified by Experts

The correct Answer is:
A

Angle of incidence is given by
`cos(pi-i)=((6sqrt3hati+8sqrt3hatj-10hatk).hatk)/(20)`
`-cosi=-(1)/(2)`
`anglei=60^circ`
From Snell's law, `sqrt2sini=sqrt3sinr`
`angler=45^circ`
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