To produce characteristic `X` - rays using a Tungsten target in an x - ray generator , the accelerating should be greater then ……. Volts and the energy of the characteristion is …… eV . (The binding energy of the intermost electron in Tungsten is - 40keV).
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To solve the problem of determining the minimum accelerating voltage required to produce characteristic X-rays using a tungsten target in an X-ray generator, we can follow these steps:
### Step 1: Understand the Concept of Characteristic X-rays
Characteristic X-rays are emitted when an electron from an outer shell falls into a vacancy created in an inner shell (typically K-shell) of an atom after an inner electron is ejected. The energy of the emitted X-ray corresponds to the difference in binding energy between the two shells.
### Step 2: Identify the Binding Energy
The problem states that the binding energy of the innermost electron in tungsten is 40 keV (or 40,000 eV). This means that to eject an electron from the K-shell, the incoming electron must have energy greater than 40 keV.
### Step 3: Determine the Minimum Accelerating Voltage
The energy of the incoming electrons in an X-ray tube is given by the equation:
\[ E = eV \]
where \( E \) is the energy in electron volts (eV), \( e \) is the charge of the electron, and \( V \) is the accelerating voltage in volts.
To produce characteristic X-rays, the accelerating voltage \( V \) must be greater than the binding energy of the innermost electron:
\[ V > 40 \text{ keV} \]
### Step 4: Conclude the Minimum Voltage
Since 1 keV = 1000 eV, we convert 40 keV to volts:
\[ V > 40,000 \text{ eV} \]
Thus, the minimum accelerating voltage required is:
\[ V > 40,000 \text{ volts} \]
### Step 5: Determine the Energy of Characteristic X-rays
The energy of the characteristic X-ray emitted will be equal to the binding energy of the electron that was ejected, which is:
\[ \text{Energy of characteristic X-ray} = 40 \text{ keV} \]
### Final Answer
- The accelerating voltage should be greater than **40,000 volts**.
- The energy of the characteristic X-ray is **40 keV**.
---
To solve the problem of determining the minimum accelerating voltage required to produce characteristic X-rays using a tungsten target in an X-ray generator, we can follow these steps:
### Step 1: Understand the Concept of Characteristic X-rays
Characteristic X-rays are emitted when an electron from an outer shell falls into a vacancy created in an inner shell (typically K-shell) of an atom after an inner electron is ejected. The energy of the emitted X-ray corresponds to the difference in binding energy between the two shells.
### Step 2: Identify the Binding Energy
The problem states that the binding energy of the innermost electron in tungsten is 40 keV (or 40,000 eV). This means that to eject an electron from the K-shell, the incoming electron must have energy greater than 40 keV.
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