The radioactive decay rate of a radioactive elemant is found to be `10^(3) ` disintegration // second at a cartain time . If the half life of the element is one second , the dacey rate after one second ….. And after three second is ……

Answer

A, C, D

Explanation

`A = A_(0) (91)/(2)) ^(0)` where ``lambda _(0) = initial activity = 1000 dps (given) `
` A = Activity after n half lives `
`At t = 1 , n = 1 :. A = 1000 ((1)/(2)) ^(1) = 500 dps `
`At t = , n = 3 :. A = 1000((1)/(2)) ^(2) = 1.25 dps`