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Fill in the blanks with appropriate items :
Consider the following reaction, `.^(2)H_(1)+.^(2)H_(1)=.^(4)He_(2)+Q`.
Mass of the deuterium atom= `2.0141 u ` , Mass of the helium atom = `4.0024 u`
This is a nuclear ________ reaction in which the energy Q is released is ______ MeV.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
This is a fusion reaction
` Energy released = (delta m) xx 931.5 MeV is ]`
`= = [2 xx 2.0141 - 4.0024 ] xx 931.5 Mev`
`= 24.03 MeV`
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