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Consider the spectral line resulting fr...

Consider the spectral line resulting from the transition `n = 2 rarr n = 1 ` in the atoms and lons given . The shortest wavelength is produced by

A

Hydrogen atiom

B

Deuterium atoms

C

Singly lonized Helium

D

Doubly lonised Lithium

Text Solution

Verified by Experts

The correct Answer is:
D
We know that
`(1)/(lambda) = RZ^(2) [(1)/(n_(2)^(2)) - (1)/(n_(1)^(2))] rArr (1)/(lambda) prop Z^(2)`
`lambda` when (1)/(LAMBDA) ` IS LARGEST I,E, WHEN `z` HAS A HIGHER VALUE `z` IS BIGHEST FOR LITHIUM .
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