SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise Comprehension Based Questions|2 Videos
MOVING CHARGES AND MAGNETISM
SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise MCQs(d )|1 Videos
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The equation: 4._(1)^(1) H^(+) rarr ._(2)^(4) He^(2+) + 2e + 26MeV represnets.
If the binding energy per nucleon in _(3)^(7) Li and _(2)^(4)He nuclei are 5.60 MeV and 7.06MeV respectively then in the reaction P +_(3)^(7) Li rarr 2 _(2)^(4) He energy of proton mnust be
The binding energy per nucleon for ""_(1)H^(2) and ""_(2)He^(4) are 1.1 MeV and 7.1 MeV respectively. The energy released when two ""_(1)H^(2) to form ""_(2)He^(4) is ………….. MeV.
Binding energy per nucleus of ._(1)^(2)H and ._(2)^(4)He are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process: ._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He
[" The binding energy of deutron "(1H^(2))" is "1.15" MeV per nucleon and an alpha "],[" particle "(2He^(4))" has a binding energy of "7.1" MeV per nucleon.Then in the "],[" reaction "1H^(2)+1H^(2)rarr_(2)He^(4)+Q],[" The energy Q released in MeV is "]
In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.
SUNIL BATRA (41 YEARS IITJEE PHYSICS)-MODERN PHYSICS-MCQ (One Correct Answer