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Onder of magnitude of density of uranium...

Onder of magnitude of density of uranium nucleus is , [m = 1.67 xx 10^(-27 kg]`

A

`10^(20)kg//m^(3)`

B

`10^(17)kg//m^(3)`

C

`10^(14)kg//m^(3)`

D

`10^(11)kg//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Naclear density of an atom number `A`,
`d = (mass)/(volume) = (A 1.67 xx 10^(-27))/((3)/(4)pi (1.25 xx 10^(-15) A^(1//3)I^(3))`
`[:.V = (4)/(3) pi r^(3), R = R_(0) A^(1//3), R_(0) = 1.25 xx 10^(-15)]`
`:.d = 2 xx 10^(17 kg//m^(3)`
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