The potential diffrence appling to an X- ray tube is `5kV` and the current through it is `3.2mA`. Then the number of electrons striking the target per second is
A
`2 xx 10 ^(16)`
B
`5 xx 10 ^(6)`
C
`1 xx 10 ^(17)`
D
`4 xx 10 ^(15)`
Text Solution
Verified by Experts
The correct Answer is:
A
KEY CONCEPT : `1 = (q)/(t) = (ne)/(t)` No , of electrons striking the target per second `= (1)/€ = 2 xx 10^(16)`
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