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A proton has kinetic energy E = 100 keV...

A proton has kinetic energy `E = 100 keV` which is equal to that of a photo is `lambda_(1)` . The ratio of `k_(2) // lambda_(1) ` is proportional to

A

`E^(2)`

B

`E^(1//2)`

C

`E^(-1)`

D

`E^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D
For photon,
`lambda_(2) = (hc)/(E )`…(i)
For proton , P = sqrt(2mE)`
`lambda_(1) = (h)/(P) = (h)/(sqrt(2mE)) ` …(ii)
`(lambda_(2))/( lambda_(1)) = (hc)/(E xx (h)/(sqrt(2mE))) prop E^(1//2)`
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