In the option given below , let `E` denote the rest mass energy of a nucleas and `n` a neutron .The correct option is

Options

A. `E(""_(92)^(236)U) gt E(""_(92)^(236)I) +E(""_(92)^(236)Y) + 2E (n)`
B. `E(""_(92)^(236)U) lt E(""_(92)^(137)I) +E(""_(39)^(97)Y) + 2E (n)`
C. `E(""_(92)^(236)U) lt E(""_(56)^(140)Ba) + E(""_(36)^(94)Kr) + 2E (n)`
D. `E(""_(92)^(236)U) =E(""_(56)^(140)Ba) +E(""_(94)^(36)Kr) + 2E (n)`

Answer

A

Explanation

Ioline and `Y`thrium` are medium sized nuclius and therefore have more binding energy per nuclius as compared to Uranium which has a big nuclus and less `B.E. `incleon.
In after work , lodine and Yurinum are more and therefore posses less energy end rest Also when Uranium nucles having kinetic energies.