Home
Class 12
PHYSICS
Let m(p) be the mass of a poton , M(1) t...

Let `m_(p)` be the mass of a poton , `M_(1)` the mass of a `_(10)^(20) Ne` nucleus and `M_(2)` the mass of a `_(20)^(40) Ca` nucleus . Then

A

`M_(2) = 2M_(1)`

B

`M_(2) gt 2M_(1)`

C

`M_(2) lt 2M_(1)`

D

`M_(1) lt 10(m_(n) + m_(p))`

Text Solution

Verified by Experts

The correct Answer is:
C, D
KEY CONCEPT : Due to mass defact (which is finally reponsible of the binding energy of the mucleus ) mass of a mecleus is always less then the sum of masses of its constiluent particles
`_(10)^(20)` Ne is made up of `10` protons `10` neutron
therefore , mass of`_(10)^(20)` Ne nucleus
`m_(1) lt 10(m_(p) + m_(n))`
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS

    SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise MCQ (One Correct Answer|1 Videos

  • ELECTROSTATICS

    SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise Comprehension Based Questions|2 Videos

  • MOVING CHARGES AND MAGNETISM

    SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise MCQs(d )|1 Videos

Similar Questions

Explore conceptually related problems

Let m_p be the mass of a proton , m_n the mass of a neutron, M_1 the mass of a ._10^20Ne nucleus and M_2 the mass of a ._20^40Ca nucleus . Then

If m_(p) and m_(n) are masses of proton and neutron respectively and M_(1) and M_(2) are masses of ._(10)MeNe^(20) and ._(20)Ca^(40) nucleus repectively, then:

If in a nuclear fusion process the masses of the fusing nuclei be m_(1) and m_(2) and the mass of the resuktant nucleus be m_(3) , then

M_p denotes the mass of a proton and M_n that of a neutron. A given nucleus, of binding energy B , contains Z protons and N neutrons. The mass M(N,Z) of the nucleus is given by.