The half - life period of a radioactive element X is same as the mean - life time of the another radicoactive electront Y initial both of then the same number of atom . Then
A
X and Y have the same decay rate initial ly
B
X and Y dacay at the same decay rate always
C
Y will dacay at a faster rate then X
D
X will dacay at a faster rate then Y
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The correct Answer is:
C
`(1_(1//2)) s = (1_(mean))Y rArr (0.693) (lambda_(z)) = (1)/(lambda_(Y))` `:. Lambda_(x) = 0.693 lambda_(Y)` `lambda_(x) lt lambda_(Y) `Now ratye of dacay `= lambdaN` initialy , number of atoms (N) of both are equal but since l`lambda_(Y) lt lambda_(x) `therefore Y will decay at a faster rate from x
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