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As electron in a hydrogen - like atom ,...

As electron in a hydrogen - like atom , is in an excited state it has a total energy of `- 3.45 eV` Calculate (i) the kinetyic energy and (ii) the de Brogle wavelength of the electron.

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The correct Answer is:
A, C, D
(i)`E_(n) = -3.4 eV`
The kinetic energy is equal to the magnitube of total energy in this case
`:. K.E = + 3.4 eV`
(ii) The de Broglie wavelength of electron
`lambda = (h)/(sqrt(2mK)) = (6.64 xx 10^(-34))/(sqrt(2 xx 9.1 xx 10^(-31) xx 3.4 xx 1.6 xx 10^(-19))) eV`
= 0.66 xx 10^(-9) m `
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