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In a photon electric experiment set upm ...

In a photon electric experiment set upm , photons of energy `5 eV` falls on the cathode having work function `3 eV` (a) if the seturation current is ` i= 4 mu A` for intensity `10^(-5) W//m^(2)`, then plot a graph between anode potential and current (b) Also draw a graph for intensity of incident radiation `2 xx 10^(-5) W//m^(2)`

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The correct Answer is:
A

`eV_(0) = hv - hv_(0) = 5 - 3 = 2 eV`
`:. V_(0) = 2 volt`
when the intensity is double , the staturation currect is also double
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