An `alpha`- particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are `lambda_a` and `lambda_p` respectively. The ratio `(lambda_p)/(lambda_a)`, to the nearest integer, is.
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C
We get that `lambda= (h)/(sqrt2 m qV)) ` `:. (lambda_(1))/(lambda_(2)) = sqrt((m_(0)q_(0))/(m_(1)q_(0))) = sqrt((4)/(1) xx (2)/(1)))= sqrt(8) = 3 `
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