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Consider a hydrogen atom with its electr...

Consider a hydrogen atom with its electron in the `n^(th)` orbital An electomagnetic radiation of wavelength `90 nm` is used to ionize the atom . If the kinetic energy of the ejected electron is `10.4 eV` , then the value of `n is ( hc = 1242 eVmn)`

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The correct Answer is:
B
`(hc)/(lambda) = (13.6)/(n^(2)) + 10.2`
`:. (1242)/(90) = (13.6)/(n^(2)) + 10.2 :. N^(2) = 4 :. N = 2 `
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