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An electron is an excited state of Li^(2...

An electron is an excited state of `Li^(2 + )`ion angular mometum `3b//2 pi ` . The de Broglie wavelength of the electron in this state is `p pi s_(0) (where a_(0) ` is the bohr radius ) The value of p is

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The correct Answer is:
B

Given `m nu r= (3 b)/(2 pi) rArr n = 3
`:. (h r)/(lambda) = (3 h)/(2 pi) [:' lambda= (h)/(m v)]`
`:. Lambda = ( 2 pi r )/(3) = (2)/(3) pui [ a_(0) (n^(2))/(z)] [:' r = a_(0) (n^(2))/(z)]`
`:. = (2)/(3) pi a_(0) [( 3 xx 3 )/(3)] = 2 ma_(0)`
:. :. n = 2 `
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