If `13.6 eV` energy is required to ionized the hydrogen atom, then the energy required to remove an electron from `n = 2 ` is
A
`10.2eV`
B
`0eV`
C
`3.4 eV`
D
`6.8 eV`
Text Solution
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The correct Answer is:
C
KEY CONCEPT : The energy of orbit of hydrogen is given by `E_(n) = (13.6)/(n^(2))eV//atom` `for n= 2, E_(n) = (-13.6)/(4) = -3.4 eV` Therefore the energy required to remove electron from `n = 2 is 3.4 eV`
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