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which a U^(238) nucleus original at rest...

which a `U^(238)` nucleus original at rest , decay by emitting an alpha particle having a speed `u` , the recoil speed of the residual nucleus is

A

`(4u)/(238)`

B

` - (4u)/(234)`

C

`(4u)/(234)`

D

`- (4u)/(238)`

Text Solution

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The correct Answer is:
To solve the problem of finding the recoil speed of the residual nucleus after a Uranium-238 nucleus decays by emitting an alpha particle, we can use the principle of conservation of momentum. Here’s a step-by-step solution: ### Step 1: Understand the Initial Conditions The Uranium-238 nucleus is initially at rest. Therefore, its initial momentum is zero. ### Step 2: Identify the Products of the Decay When Uranium-238 decays, it emits an alpha particle (which is a Helium-4 nucleus) and leaves behind a residual nucleus. The mass number of the residual nucleus can be calculated as follows: - Mass number of Uranium-238 = 238 - Mass number of alpha particle = 4 - Mass number of residual nucleus = 238 - 4 = 234 ### Step 3: Set Up the Conservation of Momentum Equation According to the conservation of momentum: \[ \text{Initial Momentum} = \text{Final Momentum} \] Since the initial momentum is zero, we can write: \[ 0 = (m_{\alpha} \cdot u) + (m_{residual} \cdot v) \] Where: - \( m_{\alpha} \) is the mass of the alpha particle (which corresponds to its mass number, 4). - \( u \) is the speed of the emitted alpha particle. - \( m_{residual} \) is the mass of the residual nucleus (which corresponds to its mass number, 234). - \( v \) is the recoil speed of the residual nucleus. ### Step 4: Substitute the Masses and Rearrange Substituting the mass numbers for the respective particles: \[ 0 = (4 \cdot u) + (234 \cdot v) \] Rearranging the equation gives: \[ 234 \cdot v = -4 \cdot u \] \[ v = -\frac{4}{234} \cdot u \] ### Step 5: Simplify the Expression Now, simplifying the fraction: \[ v = -\frac{2}{117} \cdot u \] ### Conclusion The recoil speed of the residual nucleus is: \[ v = -\frac{2u}{117} \] The negative sign indicates that the direction of the recoil speed is opposite to that of the emitted alpha particle.

To solve the problem of finding the recoil speed of the residual nucleus after a Uranium-238 nucleus decays by emitting an alpha particle, we can use the principle of conservation of momentum. Here’s a step-by-step solution: ### Step 1: Understand the Initial Conditions The Uranium-238 nucleus is initially at rest. Therefore, its initial momentum is zero. ### Step 2: Identify the Products of the Decay When Uranium-238 decays, it emits an alpha particle (which is a Helium-4 nucleus) and leaves behind a residual nucleus. The mass number of the residual nucleus can be calculated as follows: - Mass number of Uranium-238 = 238 ...
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