In the nuclear fusion reaction `_(1)^(2)H + _(1)^(3)H rarr _(2)^(4)He + n ` given that the repulsive potential energy between the two nuclei is `- 7.7 xx 10^(-14) J` , the temperature at which the gases must be beated the reaction is nearly [Boltzmann's constant `k = 1.38 xx 10^(-23) J//K]`
A
`10^(7)K`
B
`10^(5)K`
C
`10^(3)K`
D
`10^(9)K`
Text Solution
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The correct Answer is:
B, D
The average kinetic energy per molecule `= (3)/(2) kT` This kinetic energy should be able to provide the repulsive potential energy `:. (3)/(2) kT = 7.7 xx 10^(-14) ` M `rArr T = ( 2xx 7.7 xx 10^(-14))/(3 xx 1.38 xx 10^(-23)) = 3.7 xx 10^(9)`
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