The wavelength involved in the spectrum of deuterium `(_(1)^(2)D)` are slightly different from that of hydrogen spectrum because

Options

A. the size of the two nuclei are different
B. the nucllear forces are different in the two cases
C. the masses of the two neclei rae different
D. the atraction between the electron and the nucleus is different in the two cases

Answer

C

Explanation

The wavelength of spectrum is given by
`(1)/(lambda) = Rz^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) where R = (1.097 xx 10^(7))/(1 + (m)/(M))`
where m = mass of electron
M= mass of nucleus
For different `M` , R is `different and therefore `lambda` is different