The binding energies per nucleon for deuteron (`._1H^2`) and helium (`._2He^4)` are `1.1 MeV` and `7.0 MeV` respectively. The energy released when two deutrons fuse to form a helium nucleus (`._2He^4`) is……..
A
`23.6MeV`
B
`26.9MeV`
C
13.9MeV`
D
`19.2MeV`
Text Solution
Verified by Experts
The correct Answer is:
A
The neclear reaction of process is `2_(1)^(2) H rarr _(2)^(4) He` Energy released `= 4 xx (7) - 4(1.1) = 23.6 MeV`
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