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If radius of the (13)^(27) Al necleus is...

If radius of the `_(13)^(27) Al` necleus is estimated to be `3.6` fermithen the radius of `_(52)^(125)Te` nucleus be nearly

A

`8 fermi`

B

`6 fermi`

C

`5 fermi`

D

`6 fermi`

Text Solution

Verified by Experts

The correct Answer is:
B
KEY CONCEPT : `R = R_(0)(A)^(1//3)`
`:. (R_(1))/(R_(2)) = (A_(1))/(A_(2))^(1//3) = ((27)/(125))^(1//3) = (3)/(5)`
`R_(2) = (5)/(3) xx 3.6 = 6 fermi`
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