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Starting with a sample of pure .^66Cu, 3...

Starting with a sample of pure `.^66Cu`, `3/4` of it decays into `Zn` in `15` minutes. The corresponding half-life is

A

`15 minutes `

B

`10 minutes`

C

`7 (1)/(2) minutes `

D

`5 minutes`

Text Solution

Verified by Experts

The correct Answer is:
D
`(7)/(8) `of `Cu` decay in `15minutes`
`:. `Cu undecay = N = 1 - (7)/(8) = (1)/(8) = ((1)/(2))^(3)`
`:. ` no of half lifes `= 3`
`n = (I)/(T) or 3 = (15)/(T)`
`rArr T = half life period = (15)/(3) = 5 minutes`
`
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