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The half life of a radioactive substance...

The half life of a radioactive substance is `20` minutes . The approximate time interval `(t_(1) - t_(2))` between the time `t_(2)` when `(2)/(3)` of it had decayed and time t_(1)` when `(1)/(3)` of it had decay is

A

`14 min `

B

`20 min `

C

`28 min`

D

`7 min `

Text Solution

Verified by Experts

The correct Answer is:
B

Number of undecayed atom after time `t_(1)`
`(N_(0))/(3) = N_(0) e^(-lambda_(t_2))` ….(i)
Number of undecayed atom after time `t_(1)`
`(2N_(0))/(3) = N_(0) e^(-lambda_(t_2))` ….(ii)
from (i) ` e^(-lambda_(t)_2)) = (1)/(3)`
rArr - lambda t_(2) = log _(e) ((1)/(3))` ....(ii)
` from (ii) ` e^(-lambda_(t_2)) = (2)/(3)`
rArr -lambda_(t_2)) ((2)/(3))` .....(iv)
solving (iii) and (iv) , we get
`t_(1) - t_(2) = 20 min`
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