A diode detector is used to detect an amplitudennodulated wave of `60%` modulation by using a condence of capacity `250` picodarad in parallel with a load resistance `100` kilo obm find the maximum modulated which could be find the maximum modalated frequency which could be detected by it
A
`10.62 MHz`
B
`10.62 kHz`
C
`5.31 MHz`
D
`5.31 kHz`
Text Solution
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The correct Answer is:
B
Given Resistence `R = 100 kilo atom = 100 xx 10^(3) Omega` Capuclancitance `C = 250 picofarer = 250 xx 10^(-12) sec` `= 2.5 xx 10^(7) xx 10^(-12) sec` `= 2.5 xx 10^(-5) sec` The higher frequency which can be detected with tolerable distortion is ` f = (1)/(2 pi m_(0) RC) = (1)/(2 pi xx 0.6 xx 2.5 xx 10^(-5)) Hz` `= (100 xx 10^(4))/(25 xx 1.2 pi ) Hz = 10.61 Hz` This condition is obtained by appling the condition that rate of decay modulated vollage for proper detection of mdoulated single
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