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The currect voltage relation of a diode ...

The currect voltage relation of a diode is given by `1 = (e^(van v//T) -1 )mA` where the applied volied `V` is in volts and the tempetature `T` is in degree kelvin if a student make an error meassurting `+- 01 V` while measuring the current of `5 mA at 300 K` what be the error in the value of current in `mA`

A

`0.2 mA`

B

`0.02 mA`

C

`0.5 mA`

D

`0.05 mA`

Text Solution

Verified by Experts

The correct Answer is:
A
The current voltage relat5ion of diode is
`1 = (e^(1000V//T) - 1) mA `(given)
when 1 = 5 mA, (e^(1000V//T)= 6 mA`
`Also dl = (e^(1000V//T) xx (1000)/(T)
(By exponential function)
`= ( 6 mA) xx (1000)/(300) xx (0.01)`
`= 0.2mA`
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