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Hydrogen ((1)H^(1)) Deuterium ((1)H^(2)...

Hydrogen `(_(1)H^(1))` Deuterium `(_(1)H^(2))` singly omised helium `(_(1)He^(1))` and doubly ionised lithium `(_(1)Li^(6))^(++)` all have one electron around the nucleus Consider an electron transition from `n = 2 to n = 1` if the wavelength of emitted radiartion are `lambda_(1),lambda_(2), lambda_(3),and lambda_(4)`, repectivelly then approximetely which one of the following is correct ?

A

`4 lambda _(1) = 2 lambda _(2) = 2 lambda _(3)= lambda _(4)`

B

`lambda _(1) = 2 lambda _(2) = 2 lambda _(3)= lambda _(4)`

C

` lambda _(1) = lambda _(2) = 4 lambda _(3)= 9 lambda _(4) `

D

` lambda _(1) = 2 lambda _(2) = 3 lambda _(3)= 4 lambda _(4) `

Text Solution

Verified by Experts

The correct Answer is:
C
Wave number `(1)/(lambda) RZ^(2)[(1)/(n_(1)^(2)) -(1)/(n_(2)^(2))]`
`rArr lambda prop (1)/(Z^(2))`
By question `n = 1 and n_(1)= 2 `
Then `lambda_(1) = lambda_(2) = 4 lambda_(3) =9 lambda_(4) =
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