In the given figure, D and E trisect BC. Prove that 8AE = 3AC+5AD2. e mid- В DEC

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

In Fig. 7.86, if D and E trisects BC. Prove that 8AE^(2) = 3AC^(2) + 5AD^(2) .

In Figure,if AB=AC and BE=CD prove that AD=AE .

In the given figure, AC=AE, AB=AD and angleBAD=angleEAC . Prove that BC=DE .

In the given figure, AC=AE, AB=AD and angleBAD=angleEAC . Prove that BC=DE .

In the given figure, AB = AC and AD = AE. Prove that: DeltaABD~=DeltaACE

In the adjacent figure, ABC is a right angled triangle with right angle at B and points D, E trisect BC. Prove that 8AE^(2)=3AC^(2)+5AD^(2).

In Figure,ABC is a right triangle right angled at B and points DandE trisect BC. Prove that 8AE^(2)=3AC^(2)+5AD^(2)

In parallelogram ABCD, E is the mid-point of side AB and CE bisect angle BCD. Prove that : (i) AE=AD (ii) DE bisect angleADC and (iii) Angle DEC is a right angle.

In the given figure, ABC is a triangle right angled at B. D and E are ponts on BC trisect it. Prove that 8AE^(2) = 3AC^(2) + 5AD^(2) .