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Two satellites of same mass are launched...

Two satellites of same mass are launched in circular orbits at height of 2R and 3R respectively. The ration of kinetic energies is

A

`2:3`

B

`1:1`

C

`3:2`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
C
Kinetic energy is given by
`KE_(1)=(1)/(2)mv^(2)=(1)/(2)=(1)/(2)m[(GM)/(2R)]....(i)`
`KE_(2)=(1)/(2)m[(GM)/(3R)]....(ii)`
On dividing Eq.(i) by Eq.(ii) , we get
`(KE_1)/(KE_2)=(3)/(2)`
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Knowledge Check

  • Statement-1 : Two satellites of mass 3 M and M orbit the earth in circular orbits of radii r and 3r respectively. The ratio of their speeds is sqrt(3) : 1 . Statement-2 : Orbital velocity of satellite is upsilon = sqrt((GM)/(r ))

    A
    Statement -1 is true , Statement -2 is true , Statement-2 is a correct explanation of Statement -1.
    B
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    Statement-1 is true , Statement-2 is false.
    D
    Statement-1 is false , Statement-2 is true.

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