Home
Class 12
PHYSICS
A body of mass 4 kg is accelerated up by...

A body of mass 4 kg is accelerated up by a constant force, travels a distance of 5 m in the first second and a distance of 2m in the third second. The force acting on the body is

A

2N

B

4N

C

6N

D

8N

Text Solution

Verified by Experts

The correct Answer is:
A

`aRbhArra=2^(k)*b` for some integer.
Reflexive `aRa` for k=0
symmetric aRb`hArr a=2^(k)b`
`impliesb=2^(-k)ahArrbRa`
Transitive `aRbhArra=2^(k_(1))b and bRchArrb=2^(k_(2))c`
`thereforea=2^(k_(1)).2^(k_(2))c`
`impliesa=2^(k_(1)+k_(2))chArrr aRc`
`thereforeaRb,bRc`
`impliesaRc`
So, R is an equivalence relation.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PRACTICE SET 03

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 2 (MATHEMATICS)|1 Videos
  • PRACTICE SET 02

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Paper 1 (Physics)|50 Videos
  • PRACTICE SET 04

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 1 (PHYSICS & CHEMISTRY)|50 Videos

Similar Questions

Explore conceptually related problems

A body moving with uniform acceleration covers a distance of 14 m in first 2 second and 88 m in next 4 second. How much distance is travelled by it in 5^(th) second?

A body of mass 5kg is acted upon by a variable force. The force varies with the distance covered by the body as shown in figure. What is the speed of the body when it has covered 25m ? Assume that the body starts from rest.

Knowledge Check

  • A body travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is

    A
    y = 4x
    B
    y = x
    C
    y = 3x
    D
    y = 2x
  • A body travels a distance x in first two seconds and a distance y in next two seconds. The relation between x and y is

    A
    `y=4x`
    B
    `y=x`
    C
    `y=3x`
    D
    `y=2x`
  • A body travels a distance x in first two seconds anda distance y in next two seconds. The relation between and y is

    A
    y = 4x
    B
    y = x
    C
    y= 3x
    D
    y = 2x
  • Similar Questions

    Explore conceptually related problems

    A body of mass m kg starts from rest and travels a distance of s m in t seconds. The force acting on it is

    A body of mass 3 kg moving with a constant acceleration covers a distance of 10 m in the 3^(rd) second and 16 m in the 4^(th) second respectively. The initial velocity of the body is

    A body of mass 3kg moving with a constant acceleration covers a distance of 10m in the 3rd second and lbm in the 4th ssecond respectively. The initial velocity of the body is

    A body of mass 3 kg at rest is acted upon by a force and the body moves through a distance 20 m in 5 s. Force on the body is

    A constant force acts on a body of mass 0.9 kg at rest for 10 s . If the body moves a distance of 250 m, the magnitude of the force is