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A string is hanging from a rigid support...

A string is hanging from a rigid support. A transverse
pulse is excited at its free end. The speed at which the
pulse travels a distance x is proportional to

A

x

B

`(1)/(x)`

C

`(1)/(sqrt())`

D

`sqrt(x)`

Text Solution

Verified by Experts

The correct Answer is:
D
Speed of transverse pulse `v=sqrt((T)/(mu))` where `mu ` is mass of string per unit length.
For a transverse pulse `T=mu xg`
`therefore v=sqrt((mu xg)/(mu))or v prop sqrt(x)`
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