A spring is stretched by 3cm when a load...

A spring is stretched by 3cm when a load of `5.4 × 10^(6)` dyne is suspended from it. Work done will be-

`8.1xx10^(6)` erg

`6.1xx10^(6)` erg

`5.1xx 10^(6)`erg

`4.1xx 10^(6)`erg

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The correct Answer is:

Work done `=(1)/(2)xx` stretching force `xx` elongation
`W=(1)/(2)xx5.4xx10^(6)xx3=8.1xx10^(6)erg`

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