The cylindrical tube of a spray pump has a cross-section of `8 cm^2`, one end of which has `40` fine holes each of area `10^-8 m^2`. If the liquid flows inside the tube with a speed of `0.15 m min^-1`, the speed with which the liquid is ejected through the holes is.

Options

A. `50ms^(-1)`
B. `5ms^(-1)`
C. `0.05ms^(-1)`
D. `0.5ms^(-1)`

Answer

B

Explanation

According to equation of continuity ,
Av=constant
`therefore` For tube ,
`(8xx10^-8)xx((0.15)/(60))=Av_1`
For holes ,
`(40xx10^-8)xxv=A_2V_2`
`therefore A_2V_2=A_1V_1`
`therefore 40xx10^-8xxv=(8xx10^-4xx0.15)/(60)`
`rArr v=(8xx10^(-4)xx0.15)/(40xx10^(-8)xx60)=5ms^(-1)`