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If number of turns in moving coil galvan...

If number of turns in moving coil galvanometer becomes half , then the deflection for the same current will become

A

same

B

half

C

double

D

four times

Text Solution

Verified by Experts

The correct Answer is:
B

Here , `l_1=l_2,n_1=n_,n_2=(n)/(2)`
Using the relation ,
n lBA=c thetarArrl=(c theta)/(n BA)`
Hence,(l_1)/(l_2)=(theta_1)/(n_1)xx(n_2)/(theta_2)`
`rArr (theta_1)/(theta_2)=(n_1)/n_2=(n)/(n//2)=2 or theta_2=(theta_1)/(2)`
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