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In Carius method, 0.099 g organic compo...

In Carius method, `0.099 g ` organic compound gave `0.287 g AgCl.` The percentage of chlorine in the compound will be

A

28.6

B

71.7

C

35.4

D

64.2

Text Solution

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The correct Answer is:
B
`%` of chorine
`=(35.5)/(143 .5) xx ("mass of AgCl")/(" mass of the compound") xx 100`
`=(35.5)/(143.5) xx (0.287)/(0.099) xx 100 xx = 71.71 %`
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