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Direction cosines of the line (x+2)/(2)=...

Direction cosines of the line `(x+2)/(2)=(2y-5)/(3),z=-1` are

A

`4/5,3/5,0`

B

`3/5,4/5,1/5`

C

`-(3)/(5),(4)/(5),0`

D

`4/5,-2/5,1/5`

Text Solution

Verified by Experts

The correct Answer is:
A

Given equation of line is `(x+2)/(2)=(2y-5)/(3),z+1=0`
or `(x+2)/(2)=(y-(5)/(2))/((3)/(2)),z+1=0`
Hence, DR's of a line are `lt 2 , 3/2, 0gt`
Now, `sqrt(2^(2)+((3)/(2))^(2)+0)=sqrt(4+(9)/(4))=sqrt(25/4)=5/2`
`therefore` DC's of the lines are `lt (2)/(5//2), (3//2)/(5//2), 0 gt or lt 4/5, 3/5, 0 gt `
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Find the direction cosines of teh line (x-2)/(2)=(2y-5)/(-3),z=-1. Also,find the vector equation of the line.

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Knowledge Check

  • The direction cosines of the line x = y = z are

    A
    `(1)/(sqrt(3)),(1)/(sqrt(3)),(1)/(sqrt(3))`
    B
    `(1)/(3),(1)/(3),(1)/(3)`
    C
    `1,1,1`
    D
    `(2)/(sqrt(3)),(2)/(sqrt(3)),(2)/(sqrt(3))`
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