The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` is

Options

A. `1/2epsi_(0)E^(2)//Ad`
B. `epsi_(0)E^(2)//Ad`
C. `epsi_(0)E^(2)Ad`
D. `1/2epsi_(0)E^(2)Ad`

Answer

C

Explanation

Energy given by the cell
`E=CV^(2)`
Here, C = capacitance of condenser
`=(Aepsi_(0))/(d)`
V= potential difference across the plates =Ed
Therefore, `E=((Aepsi_(0))/(d))(Ed)^(2)=Aepsi_(0)E^(2)d`