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In any AC circuit the emf (e) and the cu...

In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t`
`i=I_(0) sin (omegat-phi)`
The average power in the circuit over one cycle of `AC` is

A

`(E_(0)I_(0))/(2)`

B

`(E_(0)I_(0))/(2)sinphi`

C

`(E_(0)I_(0))/(2)cos phi`

D

`E_(0)I_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
Power= rate of work done in one complete cycle.
or `P_(av)=(W)/(T)`
or `P_(av)=((E_(0)I_(0)cosphi)T//2)/(T)`
or `P_(av)=(E_(0)I_(0)cosphi)/(2)`
where `cosphi` is called the power factor of an AC circuit.
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