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A particle of mass m is projected with v...

A particle of mass m is projected with velocity making an angle of `45^(@)` with the horizontal When the particle lands on the level ground the magnitude of the change in its momentum will be .

A

2 mv

B

`mv//sqrt2`

C

`mvsqrt2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C

The horizontal momentum does not change.
The change in vertical momentum is
`mvsintheta-(-mvsintheta)=2mv(1)/(sqrt(2))`
`=sqrt(2)mv`
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