When the two inoputs of a NAND gate are shorted, the resulting gats is

Options

A. NOR
B. OR
C. NOT
D. AND

Explanation

To solve the question regarding the behavior of a NAND gate when both its inputs are shorted, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the NAND Gate**:
A NAND gate is a digital logic gate that outputs false or 0 only when both of its inputs are true or 1. The output can be expressed as:
\[ Z = \overline{A \cdot B} \]
where \( A \) and \( B \) are the inputs, and \( Z \) is the output.

2. **Shorting the Inputs**:
When both inputs of the NAND gate are shorted, we can denote both inputs as \( A \). Thus, the expression for the output becomes:
\[ Z = \overline{A \cdot A} = \overline{A} \]
This means that the output \( Z \) is the negation of input \( A \).

3. **Creating a Truth Table**:
We can create a truth table for the input \( A \) and the output \( Z \):
\[ \begin{array}{|c|c|} \hline A & Z = \overline{A} \\ \hline 0 & 1 \\ 1 & 0 \\ \hline \end{array} \]

4. **Analyzing the Truth Table**:
From the truth table, we can see that:
- When \( A = 0 \), \( Z = 1 \)
- When \( A = 1 \), \( Z = 0 \)

This behavior is characteristic of a NOT gate, which outputs the opposite of the input.

5. **Conclusion**:
Therefore, when the two inputs of a NAND gate are shorted, the resulting gate behaves like a NOT gate.

### Final Answer:
The resulting gate is a **NOT gate**.