In the expression for boyle 's law the product pV has dimensions of
A
force
B
impluse
C
energy
D
momentum
Text Solution
Verified by Experts
The correct Answer is:
b
Dimension of `Pv=[ML^(-1)T^(-2)]xx[L^(3)]=[ML^(2)T^(-2)]` (a) dimensions of force =`=MLT^(-2)` (b) Dimensions of impulse =`[(ML^(-1))]` (c ) Dimensions of energy =`[ML^(2)T^(-2)(-2)]` (d) Dimensions of momentum =`[MLT^(-1)]`
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