In a sonometer experiment the bridges are separted by a fixed distance the wire which is slightly elastic emits a tone of frequency n when held by tension T If the tension is increased to 4T the tone emitted by the wire will be of frequency
A
n
B
2n
C
slightly greater than 2n
D
slightly less than 2n
Text Solution
Verified by Experts
The correct Answer is:
d
Frequency of wave produced in the wire `n=1/2 xxsqrt(T)/(mu)` where I = length of the wire `mu` = mass per unit length T= tension in the wire Frequency produced when tension changes to T `n=1/(2I)xxsqrt(T)/(mu) rarr n =(1)/(2I)xxssqrt(4T)/(mu)`...(ii) on divinding E (i) by Eq (ii) we get `(n)/(n)=sqrt(1/4)=1/2 rarr n=2n`
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