A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration `a_(c)` is varying with time t as `a_(c) = k^(2)rt^(2)`, where k is a constant. The power delivered to the particle by the forces acting on it is :
A
`m^(2)k^(2)r^(2)t^(2)`
B
`mk^(2)r^(2)t`
C
`mk^(2)rt^(2)`
D
`mkr^(2)t`
Text Solution
Verified by Experts
The correct Answer is:
b
The centripetal accertation `a_(c)=K^(r)rt^(r ) ` or `V^(2)/ r = k^(2)rt^(2)` v= krt power =`f_(t)v cos 0^(@)=(ma_(1))(krt)` `(mkr)(krt)=mk^(2)r^(2)t`
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