A simple pendulum is oscillating with amplitue A and angular frequency `omega` At ratio of kinetic energy to potential energy is

Options

A. `(x^(2))/(A^(2)-x^(2))`
B. `(X^(2)-a^(2))/(x^(2))`
C. `(A^(2)-x^(2))/(x^(2))`
D. `(A-x)/(x)`

Answer

a

Explanation

Kinetic energy of pendulum osciallating with amplitude A and angular frequency `omega` at displacement x from mean position is
`KE =1/2 k(A^(2)-x^(2))`

potential energy of pendulum at displaceemnt x from mean positon is
`PE =1/2 kx^(2)`
`therefore (KE)/(PE)=(1/2k(A^(2)-x^(2)))/(1/2kx^(2))=(A^(2)-x^(2))/(x^(2))`