A rope 1 cm in diameter breaks if the tension in it exceeds 500 N. The maximum tension that any be given to a similar rope of diameter 2 cm is
A
2000 N
B
1000 N
C
500 N
D
250 N
Text Solution
Verified by Experts
The correct Answer is:
a
We know that young modulus `Y =("stress") /("strain")` `y=(T)/(Axx"Strain")` for same type of wire `(y)/("strain")=(T)/(A) rarr (T_(1))/(A_(1))=(T_(2))/(A_(2))` where T s are tensions in the wires and A 's are areas of cross section or `(500)/(pir_(1)^(2))=(T_(2))/(pir_(2)^(2))` or `(500)/((1cm)^(2))=(T_(2))/(2cm)^(2)` `T_(2)=4xx500=2000 N`
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