A large number of liquid drops each of radius 'a' coalesce to form a single spherical drop of radish b. The energy released in the process is converted into kinetic energy of the big drops formed. The speed of big drop will be
A
`[(6T)/(rho)(1/a-1/b)]^(1//2)`
B
`[(6T)/(rho)(1/b-1/a)]^(1//2)`
C
`[(rho)/(6T)(1/a-1/b)]^(1//2)`
D
`[(rho)/(6T)(1/b-1/a)]^(-1//2)`
Text Solution
Verified by Experts
The correct Answer is:
a
Suppose n number of liquid drops are merged equating initial and final volume we have `v_(i)=v_(t)` `rarr n xx 4/3 pi a^(3)=4/3 pi b^(3)` `rarr b=(n)^(1//3)a rarr n =(b/a)^(3)` initial surface energy `u_(i)=nxx 4pi a^(2)xxS` final surface energy `u_(f)=4pib^(2)xxS` change in surface energy speed of the bigger drop `v=[(6T)/(p)(1/a-1/b)]^(1//2)`
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