The distances of a point on the screen from two slits in biprism experiment is `1.8xx10^(5)` m and `1.23xx10^(5)` m if wavelength of light used is 6000 Å then fringe formed at that point is
A
10th bright
B
10 th dark
C
9th bright
D
9th dark
Text Solution
Verified by Experts
The correct Answer is:
c
Path difference between light rays coming from two slits `Delta x =1.8 xx10^(-5)=1.23 xx10^(-5)` `=10^(-5)(1.85-1.23)=0.57xx10^(-5)=57xx10^(-7)` `=57000xx10^(-10)=57000 A` it is not an integral multiple of wavelength thus only dark fringes are possible for nth drk fringe `Delta x = (2n-1)(lambda)/(2)` `rarr 2n-1 =2xx57/6=57/3=19` `rarr 2n-1 =19` or 2n=20 ro n=10 thus 10th dark fringle is formed
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