The electric field intensity at point near and outside the surface of a charged conductor of any shate is `E_(1)` the elecric field intensity due to uniformly charged conductor of any shape is `E_(1)` the electric field intensity due ot uniformly charged infinite thin plane sheet is `E_(2)` the relation between `E_(1)` and `E_(2)` is

Options

A. `2E_(1)=E_(2)`
B. `E_(1)=E_(2)`
C. `E_(1)=2E_(2)`
D. `E_(1)=4E_(1)`

Answer

b

Explanation

Electric field intensity at a point near and outside the surface of any charged conductor is given by
`E_(1)=(sigma)/(epsilon_(0))`
where `sigma` is charge density (charge per unit area) at a point
Electric field intensity due to uniformly charged infinite thin plane sheet is givne by
`E_(2)=(sigma)/(2 epsilon_(0))`
from eqs (i) and (ii) we have
`e_(1)=2/2xx(sigma)/(epsilon_(0))=2xxE_(2)rarrE_(1)=2E_(2)`