A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will be
A
2.00 m
B
2.25 m
C
2.50 m
D
2.75 m
Text Solution
Verified by Experts
The correct Answer is:
a
Balancing condition of potentiometer is given by if `I_(1)` is incressed by 1m then new length will `I_(1)=10m+1m=11m` `therefore` new balancing length of wire `(l_(2))` is `(mu^_(1))/(l_(2))=(E_(1))/(E_(2)) rarr (11)/(l_(2))=4 therefore L_(2)=11/4=2.75 m`
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